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This is one of our many quizzes on Dilution. Click on this to access more such competitive quizzes on Acids, Bases And Salts.

Dilution Quiz 2

chemistry

  A beaker contains acetone, in concentrated form. Now, water is added to it dropwise, so that an ideal solution is formed. Choose which is correct option:

 In ideal solution, force of bond AA and BB are equal to force of bond AB.

On dilution, an ideal solution is formed. In ideal solution, $\Delta H=\Delta V=0$.

 Ravi prepared a compound A and found that it is a non-volatile compound. Ravi added the same compound A to the water. What will happen to the vapour pressure of the solution?

 The vapour pressure of solution is going to decrease if the solution contains a non-volatile solute in it. The relative lowering of vapour pressure when a non-volatile solute is added is $\dfrac{{{p}^{0}}-{{p}_{s}}}{{{p}^{0}}}=\dfrac{n}{N}$

The compound A is non-volatile means it is going to occupy the surface of the solution and decrease the vapour pressure of the solution. 

 A solution contains 0.5M NaCl solution(100mL). Now, this solution is diluted with water, and the new concentration of the salt is 0.1M. What is the volume of solution?

  ${{M}_{1}}{{V}_{1}}={{M}_{2}}{{V}_{2}}$

 $ m\times 0.1=0.5\times 100 \\ \Rightarrow m=\dfrac{0.5\times 100}{0.1}=500g $

 There are two beakers, beaker A has $HCl$ solution and the other beaker has $KOH$ solution. Now, water is added to both of the beakers. What will be the effect of pH on both of the beakers?

 Water is neutral and will try to bring pH of the solutions close to its value.

 Beaker A has an acid solution, hence pH is low, so on dilution pH increases and tends to be neutral. Beaker B has a basic solution, so on dilution, pH decreases and tends to be neutral.

 Check the following graph as KCl solution is diluted:<br><img  src="https://cmds-vedantu.s3.ap-southeast-1.amazonaws.com/prod/question-sets/fd2addb3-1094-4b76-9c57-6220752f8c678274005125241202352.png"/><br>At normal room temperature, the following table gives the data:<img  src="https://cmds-vedantu.s3.ap-southeast-1.amazonaws.com/prod/question-sets/303619d1-fd1f-4d44-83f3-b195f10a1aad2747119107341276218.png"/><br>Find the constant “A”, from the Debye Huckel Onsager reaction:

 Use Debye Huckel Onsager equation which is ${{\Delta }_{m}}={{\Delta }^{0}}_{m}-A{{(C)}^{\dfrac{1}{2}}}$.

 $A=-slope\,of\,line=-\dfrac{1.52(Sc{{m}^{2}}mo{{l}^{-1}})}{-17.38\times {{10}^{-3}}{{(mol{{L}^{-1}})}^{\dfrac{1}{2}}}}=87.45$