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This is the second of our many quizzes on Balancing equations. Click on this to access more such competitive quizzes on [parent topic name].

Balancing equations Quiz 2

chemistry

 The balanced chemical reaction for the synthesis of lead(II) chloride by precipitation is  

 Since the oxidation state of acetate ion is -1, $C{{H}_{3}}COOPb$ will not exist, hence option (b) is incorrect. Option (c) and (d) have unequal molecules of reactants and products. Hence the correct option is (a).

In the reaction $FeS{{O}_{4}}+HN{{O}_{3}}+{{H}_{2}}S{{O}_{4}}\to Fe{{(S{{O}_{4}})}_{3}}+{{H}_{2}}O+NO$ The stoichiometric coefficients of the compounds will be

 This is a redox reaction and can be balanced using the half reaction method or oxidation number method.

$6FeS{{O}_{4}}+2HN{{O}_{3}}+3{{H}_{2}}S{{O}_{4}}\to 3Fe{{(S{{O}_{4}})}_{3}}+4{{H}_{2}}O+2NO\\ $ All the atoms and the charges are equalized, the equation is balanced.

$P{{b}_{3}}{{O}_{4}}+xHN{{O}_{3}}\to yPb{{(N{{O}_{3}})}_{2}}+z{{H}_{2}}O+Pb{{O}_{2}}\downarrow $ Identify x, y, and z.

 This is a type of redox reaction. $P{{b}_{3}}{{O}_{4}}$ acts as both the oxidizing and the reducing agent.

$P{{b}_{3}}{{O}_{4}}+4HN{{O}_{3}}\to 2Pb{{(N{{O}_{3}})}_{2}}+2{{H}_{2}}O+Pb{{O}_{2}}\downarrow \\ $ All the atoms and the charges are equalized, the equation is balanced.

 Rama burns 3 mole of barium azide. How many moles of nitrogen gas will she obtain?

 Barium azide $Ba{{({{N}_{3}})}_{2}}$ gives pure nitrogen gas upon thermal decomposition.

This question can be solved by determining the balanced chemical equation of thermal decomposition of barium azide. $\\ Ba{{({{N}_{3}})}_{2}}\xrightarrow{\Delta }Ba+3{{N}_{2}}\\ $ One mole of barium azide gives 3 moles of nitrogen gas. 3 moles of barium azide will give 9 moles of nitrogen gas.

A reaction takes place as follows <img src="https://cmds-vedantu.s3.ap-southeast-1.amazonaws.com/prod/question-sets/6bb7fdeb-3a4c-4c89-af93-d7eb138af72d7463553755827466269.png"/> If the white atoms = X, the black atoms = Y, and the red atoms = Z, the formula of P will be

 In a balanced chemical equation, the number of atoms on the reactant side and the product side is equal for each element.

Since four X atoms and two Z atoms unaccounted for form 2 molecules, the balanced equation will be as follows $\\ Y{{X}_{4}}+2{{Z}_{2}}\to Y{{Z}_{2}}+2{{X}_{2}}Z \\ \text{Hence P is }{{X}_{2}}Z$