How do you write the expression \[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ }\] as sine, cosine, or tangent of an angle?
Answer
624.3k+ views
Hint:This question involves the arithmetic operations like addition/ subtraction/ multiplication/ division. To solve this problem we need to know the basic trigonometric identities. We need to know how to compare the given expression with trigonometric identities to make an easy calculation. The final answer would be a simplified form of the given expression.
Complete step by step solution:
The given expression in the question is shown below,
\[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } \to \left( 1 \right)\]
We know that,
\[\cos \left( {A + B} \right) = \cos A\cos B - \sin A\sin B\]
The above equation can also be written as,
\[\cos A\cos B - \sin A\sin B = \cos \left( {A + B} \right) \to \left( 2 \right)\]
Let’s compare the equation \[\left( 1 \right)\]and\[\left( 2 \right)\], we get
\[\left( 1 \right) \to \cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ }\]
\[\left( 2 \right) \to \cos A\cos B - \sin A\sin B = \cos \left( {A + B} \right)\]
By comparing these two equations we get,
The value of \[A\] is \[{25^ \circ }\] and the value of \[B\] is \[{15^ \circ }\]
So, the equation \[\left( 2 \right)\] can also be written as,
\[\left( 2 \right) \to \cos A\cos B - \sin A\sin B = \cos \left( {A + B} \right)\]
\[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = \cos \left( {{{25}^ \circ } + {{15}^ \circ }} \right)\]
By using addition operation to solve the above equation we get,
\[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = \cos \left( {{{35}^ \circ }}
\right)\]
So, the final answer is,
\[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = \cos \left( {{{35}^ \circ }}
\right)\]
We won’t find the value \[\cos \left( {{{35}^ \circ }} \right)\] from the above equation, because in this question they ask the final answer in sine, cosine, or tangent of an angle. Here angle is the cosine of \[{35^ \circ }\].
Note: This question describes the operation of arithmetic functions like addition/ subtraction/ multiplication/ division. Remember the basic trigonometric identities to solve these types of questions. Note that the final answer would contain angle instead of numbers for these types of questions. So we don’t need to calculate the cosine angle in the final answer. Because in this question they ask the final answer in the form of sine, cosine, or tangent of an angle. Also, note that \[\cos \left( { - \theta } \right)\] it also can be written as \[\cos \theta \].
Complete step by step solution:
The given expression in the question is shown below,
\[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } \to \left( 1 \right)\]
We know that,
\[\cos \left( {A + B} \right) = \cos A\cos B - \sin A\sin B\]
The above equation can also be written as,
\[\cos A\cos B - \sin A\sin B = \cos \left( {A + B} \right) \to \left( 2 \right)\]
Let’s compare the equation \[\left( 1 \right)\]and\[\left( 2 \right)\], we get
\[\left( 1 \right) \to \cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ }\]
\[\left( 2 \right) \to \cos A\cos B - \sin A\sin B = \cos \left( {A + B} \right)\]
By comparing these two equations we get,
The value of \[A\] is \[{25^ \circ }\] and the value of \[B\] is \[{15^ \circ }\]
So, the equation \[\left( 2 \right)\] can also be written as,
\[\left( 2 \right) \to \cos A\cos B - \sin A\sin B = \cos \left( {A + B} \right)\]
\[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = \cos \left( {{{25}^ \circ } + {{15}^ \circ }} \right)\]
By using addition operation to solve the above equation we get,
\[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = \cos \left( {{{35}^ \circ }}
\right)\]
So, the final answer is,
\[\cos {25^ \circ }\cos {15^ \circ } - \sin {25^ \circ }\sin {15^ \circ } = \cos \left( {{{35}^ \circ }}
\right)\]
We won’t find the value \[\cos \left( {{{35}^ \circ }} \right)\] from the above equation, because in this question they ask the final answer in sine, cosine, or tangent of an angle. Here angle is the cosine of \[{35^ \circ }\].
Note: This question describes the operation of arithmetic functions like addition/ subtraction/ multiplication/ division. Remember the basic trigonometric identities to solve these types of questions. Note that the final answer would contain angle instead of numbers for these types of questions. So we don’t need to calculate the cosine angle in the final answer. Because in this question they ask the final answer in the form of sine, cosine, or tangent of an angle. Also, note that \[\cos \left( { - \theta } \right)\] it also can be written as \[\cos \theta \].
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

