Two spheres of equal masses, one of which is a thin spherical shell and the other a solid, have the same moment of inertia about their respective diameters. The ratio of their radii well be.
$\begin{align}
  & \text{A}.\text{ }5:7 \\
 & \text{B}.\text{ }3:5 \\
 & \text{C}.\text{ }\sqrt{3:}\sqrt{5} \\
 & \text{D}.\text{ }\sqrt{3:}\sqrt{7} \\
\end{align}$

Hint: We have to find a ratio of thin spherical shell and a solid shell. So first we will find the moment of inertia of both the shells and it is given that the moment of inertia in both cases are the same so we will equate the equations and further solve to find their ratios.

Complete answer:



Moment of inertia of thin spherical shell is given by
${{I}_{1}}=\dfrac{2}{3}MR_{1}^{2}$
Moment of inertia of thin spherical shell is given by
${{I}_{2}}=\dfrac{2}{5}MR_{2}^{2}$


 As both the masses of spheres are the same let the mass be m.
Let the radii of the thin spherical shell be\[{{R}_{1}}\].
The radii of the thin spherical shell be${{R}_{2}}$.
Moment of inertia of thin spherical shell about the diameter is given by
${{I}_{1}}=\dfrac{2}{3}MR_{1}^{2}$
Moment of inertia of thin spherical shell about the diameter is given by
${{I}_{2}}=\dfrac{2}{5}MR_{2}^{2}$
As given in the question both the moment of inertia are same,
Hence equating both the moment of inertia we get
$\dfrac{2}{3}MR_{1}^{2}=\dfrac{2}{5}MR_{2}^{2}$
Both the masses are same therefore,

$\begin{align}
  & \dfrac{2}{3}MR_{1}^{2}=\dfrac{2}{5}MR_{2}^{2} \\
 & \dfrac{R_{1}^{2}}{R_{2}^{2}}=\dfrac{3}{5} \\
 & {{\left( \dfrac{{{R}_{1}}}{{{R}_{2}}} \right)}^{2}}=\dfrac{3}{5} \\
 & \dfrac{{{R}_{1}}}{{{R}_{2}}}=\dfrac{\sqrt{3}}{\sqrt{5}} \\
\end{align}$

So the ratio obtained is $\sqrt{3:}\sqrt{5}$.

So, the correct answer is “Option C”.

Additional Information:
Physical significance of moment of inertia is the mass of a body that resists a change in its state of linear motion, it is a measure of its inertia in a linear motion.

Note:
Moment of inertia about the rigid body about a fixed axis is defined as the sum of the product of the masses of the particles constituting the body and the squares of their respective axis from the axis of rotation.
$I=\sum\limits_{i=1}^{n}{{{m}_{i}}r_{i}^{2}}$
We use the above expression to calculate the moment of inertia.
Solid sphere and spherical shell have the same radius if they are of the same volume. The difference between both is just that spherical shell is hollow from the inside.