The value of $ \sin {10^ \circ } + \sin {20^ \circ } + \sin {30^ \circ }........\sin {360^ \circ } $ is equal to
Answer
631.8k+ views
Hint: Though this is an easy sum, it is very tricky and difficult if one is not well acquainted with the identities and values of Trigonometric functions. This sum involves use of sine properties . The property which we are going to use in this particular sum is $ \sin (360 - \theta ) = - \sin \theta $ . We can also use the graph to understand this property or just memorize these types of expressions for all the trigonometric functions.
Complete step-by-step answer:
From the given sum we will have club expressions in which the sum of angle turns out to be $ {360^ \circ } $
Thus we club $ \sin {10^ \circ }\& \sin {350^ \circ } $ , $ \sin {20^ \circ }\& \sin {340^ \circ } $ $ \sin {30^ \circ }\& \sin {330^ \circ } $ till we reach $ {360^ \circ } $ .
Total numbers of terms involved in the given expression are $ {36^ \circ } $ .
If we club $ 2 $ terms, then we will be having $ 18 $ pairs.
In order to solve the sum we will use the property $ \sin (360 - \theta ) = - \sin \theta $ . This will help us in finding the solution for each pair.
Now the last step is finding the value of each pair in order to reach the final answer.
Considering the $ 1st $ pair $ \sin {350^ \circ } $
We can write $ \sin {350^ \circ } = \sin ({360^ \circ } - {10^ \circ }).....(1) $
From Equation $ 1 $ we can say that the value of $ \sin {350^ \circ } $ is the same as $ - \sin {10^ \circ } $ .
$ \therefore $ Pair one which is $ \sin {10^ \circ }\& \sin {350^ \circ } $ can now be written as $ \sin {10^ \circ }\& - \sin {10^ \circ } $
Since the numerical involves the sum of series, the value of Pair 1 would become $ 0 $ .
Similarly for all the pairs the value would be $ 0 $ .
$ \therefore $ The sum of the series would be $ 0 $
So, the correct answer is “0”.
Note: This sum is just the application of the properties of trigonometric functions. If the student finds it difficult in memorizing the properties it is advisable to learn them by making graphs. Graphical representation is another method of understanding these properties. Numericals and word problems from the chapter of Trigonometry would be only based on the properties and expressions. Thus memorizing the properties is of utmost importance.
Complete step-by-step answer:
From the given sum we will have club expressions in which the sum of angle turns out to be $ {360^ \circ } $
Thus we club $ \sin {10^ \circ }\& \sin {350^ \circ } $ , $ \sin {20^ \circ }\& \sin {340^ \circ } $ $ \sin {30^ \circ }\& \sin {330^ \circ } $ till we reach $ {360^ \circ } $ .
Total numbers of terms involved in the given expression are $ {36^ \circ } $ .
If we club $ 2 $ terms, then we will be having $ 18 $ pairs.
In order to solve the sum we will use the property $ \sin (360 - \theta ) = - \sin \theta $ . This will help us in finding the solution for each pair.
Now the last step is finding the value of each pair in order to reach the final answer.
Considering the $ 1st $ pair $ \sin {350^ \circ } $
We can write $ \sin {350^ \circ } = \sin ({360^ \circ } - {10^ \circ }).....(1) $
From Equation $ 1 $ we can say that the value of $ \sin {350^ \circ } $ is the same as $ - \sin {10^ \circ } $ .
$ \therefore $ Pair one which is $ \sin {10^ \circ }\& \sin {350^ \circ } $ can now be written as $ \sin {10^ \circ }\& - \sin {10^ \circ } $
Since the numerical involves the sum of series, the value of Pair 1 would become $ 0 $ .
Similarly for all the pairs the value would be $ 0 $ .
$ \therefore $ The sum of the series would be $ 0 $
So, the correct answer is “0”.
Note: This sum is just the application of the properties of trigonometric functions. If the student finds it difficult in memorizing the properties it is advisable to learn them by making graphs. Graphical representation is another method of understanding these properties. Numericals and word problems from the chapter of Trigonometry would be only based on the properties and expressions. Thus memorizing the properties is of utmost importance.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

