Solve: $\dfrac{7}{y} + 1 = 29$
Answer
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Hint: This is a linear equation in one variable. This question will be solved by taking $y$to one side and all the constants to the other side.
Complete Step by Step Solution:
We have $\dfrac{7}{y} + 1 = 29$
By multiplying both the sides by $y,$we get
$7 + y = 29y$
Now take $y$to the right side of the equation
$ \Rightarrow 7 = 29y - y$
$ \Rightarrow 7 = 28y$
Rearranging the equation, we get
$28y = 7$
Divide both the sides by 28
$ \Rightarrow y = \dfrac{7}{{28}}$
$ \Rightarrow y = \dfrac{1}{4}$
Note: You can observe that, in this question, the variable is in the denominator. In such a case, the value of the denominator cannot be equal to zero. Because if the variable becomes zero then the fraction will become infinity, which will give no solution.
Complete Step by Step Solution:
We have $\dfrac{7}{y} + 1 = 29$
By multiplying both the sides by $y,$we get
$7 + y = 29y$
Now take $y$to the right side of the equation
$ \Rightarrow 7 = 29y - y$
$ \Rightarrow 7 = 28y$
Rearranging the equation, we get
$28y = 7$
Divide both the sides by 28
$ \Rightarrow y = \dfrac{7}{{28}}$
$ \Rightarrow y = \dfrac{1}{4}$
Note: You can observe that, in this question, the variable is in the denominator. In such a case, the value of the denominator cannot be equal to zero. Because if the variable becomes zero then the fraction will become infinity, which will give no solution.
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