Solve $7{x^2} - 14x = 0$
Answer
613.2k+ views
Hint:
The given problem requires us to solve an equation. The given equation can be reduced to a simple quadratic equation using a substitution. There are various methods that can be employed to solve a quadratic equation like completing the square method, using quadratic formulas and by splitting the middle term.
Complete step by step solution:
In the given question, we are required to solve the equation $7{x^2} - 14x = 0$.
Quadratic equations can be solved by various methods like splitting the middle term, using the quadratic formula, factoring the common factor, and completing the square method.
We can solve the given equation by any of the methods.
Consider the equation $7{x^2} - 14x = 0$.
The equation can be factorized easily as x can be taken out common from both the terms in the equation.
So, $7{x^2} - 14x = 0$
Taking x common from both the terms, we get,
$ \Rightarrow x\left( {7x - 14} \right) = 0$
Taking $7$ common from both the terms, we get,
$ \Rightarrow 7x\left( {x - 2} \right) = 0$
Dividing both sides of the equation by $7$,
$ \Rightarrow x\left( {x - 2} \right) = 0$
Now, either $x = 0$ or $\left( {x - 2} \right) = 0$.
Either $x = 0$ or $x = 2$.
So, the roots of the given equation $7{x^2} - 14x = 0$ are: $x = 0$ and $x = 2$.
Note:
Quadratic equations are the polynomial equations with degree of the variable or unknown as $2$. Quadratic equations can be solved by splitting the middle term, factoring common factors, using the quadratic formula and completing the square method. The given equation can be solved by each and every method listed above.
The given problem requires us to solve an equation. The given equation can be reduced to a simple quadratic equation using a substitution. There are various methods that can be employed to solve a quadratic equation like completing the square method, using quadratic formulas and by splitting the middle term.
Complete step by step solution:
In the given question, we are required to solve the equation $7{x^2} - 14x = 0$.
Quadratic equations can be solved by various methods like splitting the middle term, using the quadratic formula, factoring the common factor, and completing the square method.
We can solve the given equation by any of the methods.
Consider the equation $7{x^2} - 14x = 0$.
The equation can be factorized easily as x can be taken out common from both the terms in the equation.
So, $7{x^2} - 14x = 0$
Taking x common from both the terms, we get,
$ \Rightarrow x\left( {7x - 14} \right) = 0$
Taking $7$ common from both the terms, we get,
$ \Rightarrow 7x\left( {x - 2} \right) = 0$
Dividing both sides of the equation by $7$,
$ \Rightarrow x\left( {x - 2} \right) = 0$
Now, either $x = 0$ or $\left( {x - 2} \right) = 0$.
Either $x = 0$ or $x = 2$.
So, the roots of the given equation $7{x^2} - 14x = 0$ are: $x = 0$ and $x = 2$.
Note:
Quadratic equations are the polynomial equations with degree of the variable or unknown as $2$. Quadratic equations can be solved by splitting the middle term, factoring common factors, using the quadratic formula and completing the square method. The given equation can be solved by each and every method listed above.
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