How do you solve $ - 3(4x + 3) + 4(6x + 1) = 43$?
Answer
626.7k+ views
Hint:The above question is based on algebraic equations. The main approach towards solving the expression is to simplify by opening the parenthesis and multiplying the terms outside the parentheses with the terms inside the brackets and performing mathematical operations.
Complete step by step solution:
The above equation is an algebraic equation. It is made up of variables, constants along with mathematical operations like addition, subtraction, division and multiplication. Here there is an equal sign which has Left hand side and right-hand side of it. Both the sides are connected by equal to sign.
In the equation we have an unknown variable \[x\],so we need to find the value of it.
For that we need to isolate variables and constants. Keeping the variable on the left hand side and shifting others on the right-hand side.
So, first we will simplify by opening the parenthesis and multiplying the terms outside the brackets with the terms which are present inside.
\[
\Rightarrow - 3(4x + 3) + 4(6x + 1) = 43 \\
\Rightarrow - 12x - 9 + 24x + 4 = 43 \\
\]
So, on simplifying we get the above equation. Now we will perform mathematical operations on all the terms.
\[
\Rightarrow 12x - 5 = 43 \\
\Rightarrow x = \frac{{48}}{{12}} = 4 \\
\]
Therefore, by shifting all the terms on the right-hand side and isolating the term on the left-hand side we get the value of \[x\]as 4.
Note: An important thing to note is that equations and expressions have two different meanings. The above question given, has an equation which means two sides are connected with equal to sign whereas an expression lacks the equal to sign variable, constants and mathematical operations
Complete step by step solution:
The above equation is an algebraic equation. It is made up of variables, constants along with mathematical operations like addition, subtraction, division and multiplication. Here there is an equal sign which has Left hand side and right-hand side of it. Both the sides are connected by equal to sign.
In the equation we have an unknown variable \[x\],so we need to find the value of it.
For that we need to isolate variables and constants. Keeping the variable on the left hand side and shifting others on the right-hand side.
So, first we will simplify by opening the parenthesis and multiplying the terms outside the brackets with the terms which are present inside.
\[
\Rightarrow - 3(4x + 3) + 4(6x + 1) = 43 \\
\Rightarrow - 12x - 9 + 24x + 4 = 43 \\
\]
So, on simplifying we get the above equation. Now we will perform mathematical operations on all the terms.
\[
\Rightarrow 12x - 5 = 43 \\
\Rightarrow x = \frac{{48}}{{12}} = 4 \\
\]
Therefore, by shifting all the terms on the right-hand side and isolating the term on the left-hand side we get the value of \[x\]as 4.
Note: An important thing to note is that equations and expressions have two different meanings. The above question given, has an equation which means two sides are connected with equal to sign whereas an expression lacks the equal to sign variable, constants and mathematical operations
Recently Updated Pages
Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

Trending doubts
One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

What do you mean by retardation What is its SI uni class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Difference between physical and chemical change class 11 chemistry CBSE

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

