Find the area of the figure:

Hint: We have a rectangle and also the dimensions of the rectangle are given in the figure. We must use the fact that the area of the rectangle is given by A = lb, where l is the length of the rectangle and b is the breadth of the rectangle.

Complete step-by-step answer:
Before solving the question, we should know that if the length of the rectangle is equal to l and the breadth of the rectangle is equal to b, then the area of the rectangle is equal to the product of l and b.

From the diagram, it is clear that the AB is parallel to CD and BC is parallel to AD. So, the length of AB is equal to CD. In the similar way, the length of BC is equal to the length of AD. Hence, we can say that the given figure is a rectangle.

So, we can represent the obtained rectangle as shown in the above figure.
So, it is clear that the length of the rectangle is equal to 7 meters and the breadth of the rectangle is equal to 4 meters.
\[\begin{align}
  & l=7......(1) \\
 & b=4......(2) \\
\end{align}\]
We know that if the length of the rectangle is equal to l and the breadth of the rectangle is equal to b, then the area of the rectangle is equal to the product of l and b.
Let us assume that the area of the rectangle is equal to A.
\[\Rightarrow A=lb.....(3)\]
Now we will substitute equation (1) and equation (2) in equation (3), we get
\[\begin{align}
  & \Rightarrow A=(7)(4) \\
 & \Rightarrow A=28.......(4) \\
\end{align}\]
From equation (4), it is clear that the area of the given figure is equal to \[28{{m}^{2}}\].


Note:Students should know the perfect definition of area. If a student did not have a clear view on the concept of area, then it is not possible to do this question. So, a clear view is required to solve this problem. S