Find the actual lower class limits, upper class limits and the mid-values of the classes: 9.5, 14.5, 19.5, 24.5, 29.5, 34.5 and 39.5, 44.5, 49.5.

Hint: In order to solve this problem we need to know that 1 is the lower limit and 5 is the upper limit. Similarly, 6 is the lower limit and 10 is the upper limit of the next class interval 6 – 10. Clearly, the upper limit of a class interval is different from the lower limit of the next class interval in case of non-overlapping groups.

Complete step-by-step answer:
The given numbers are 9.5, 14.5, 19.5, 24.5, 29.5, 34.5 and 39.5, 44.5, 49.5.
Let the least term of a sequence be a term which is smaller than all but a finite number of the terms which are equal. Then it is called the lower limit of the sequence. A lower limit of a series.
Actual lower limits are 9.5, 19.5, 29.5 and 39.5.
The upper class limit of a class is the largest data value that can go into the class. Class limits have the same accuracy as the data values; the same number of decimal places as the data values.
Actual upper limits are 19.5, 29.5, 39.5 and 49.5.
Mid -value: It is the average of the lower limit and the upper limit of a class. Example: Lower limit of the first class is 0 and the upper limit is 10. Therefore, the mid-value of the first class is $\dfrac{{0 + 10}}{2}$that is, 5.

Note: To solve this problem we need to remember these concepts since these concepts are not so important but it can arise any time so remembering this would be a better option and knowing these concepts will solve such types of problems.