Find height of parallelogram whose area is \[54c{m^2}\] and base is \[15cm\].

Hint: While calculating the height of parallelogram, we divide the area of parallelogram by its base and we get corresponding height.

Formula: Area of parallelogram \[ = Base \times height.\]

Complete step by step answer:
(1) Given area of parallelogram \[ = 54c{m^2}\;\]
Base of parallelogram \[ = 15cm\]
We know that area of parallelogram is given as a product of base and its corresponding height.
Area of parallelogram \[ = B \times H\].
Here, $B$ is base and $H$ is height.
(2) Let \[AB = 15cm\] (given base of parallelogram)
DM is its corresponding height.
(3) Using values in formula
\[Area\,\,of\,\,paralle\log ram = base \times height\]
\[ \Rightarrow \,54 = 15 \times height\]
\[ \Rightarrow \,height\,\, = \dfrac{{54}}{{15}}\]
height $ = \dfrac{{18}}{5}$
\[ \Rightarrow \,height\,\, = 3.6cm\]
Therefore, the height of the parallelogram is \[3.6cm\].

Note: In parallelogram, opposite sides are equal, opposite angles are equal, opposite lines are parallel and diagonal bisect each other. While calculating area of parallelogram, base and corresponding altitude is to be taken.