How do you factor by grouping ${x^3} + 4{x^2} + 8x + 32$?
Answer
624.9k+ views
Hint: In this question, we want to find factors of the given expression. For that, we will use the grouping method. The first group has the first two terms, and the second group has another two terms. Then, take out the greatest common factor from each group. Now, take out the common term.
Complete step-by-step answer:
In this question, we want to factor the expression ${x^3} + 4{x^2} + 8x + 32$ by grouping the terms.
Let us make a pair of terms of the given expression.
$ \Rightarrow {x^3} + 4{x^2} + 8x + 32$
Now, the first group has the first two terms, and the second group has another two terms.
Here, the first group will be ${x^3} + 4{x^2}$ , and the second group will be $8x + 32$
So, let us write them into brackets.
$ \Rightarrow \left( {{x^3} + 4{x^2}} \right) + \left( {8x + 32} \right)$
Now, take out the greatest common factor from each group.
In the first group, ${x^2}$ is the greatest common factor.
And in the second group, 8 is the greatest common factor.
Therefore, we will get:
$ \Rightarrow {x^2}\left( {x + 4} \right) + 8\left( {x + 4} \right)$
Now, take out the common term to get factors.
Here, $x + 4$ is the common term in the above expression.
So, we will get:
$ \Rightarrow \left( {x + 4} \right)\left( {{x^2} + 8} \right)$
Hence, the factors of the given expression ${x^3} + 4{x^2} + 8x + 32$ are $x + 4$ and ${x^2} + 8$.
Note:
One important thing is, we can always check our work by multiplying out factors back together, and check that we have got back the original answer.
To check our factorization, multiplication goes like this:
$ \Rightarrow \left( {x + 4} \right)\left( {{x^2} + 8} \right)$
Break the first bracket and multiply it with another bracket.
So,
$ \Rightarrow x\left( {{x^2} + 8} \right) + 4\left( {{x^2} + 8} \right)$
Let us apply multiplication to remove brackets.
$ \Rightarrow {x^3} + 8x + 4{x^2} + 32$
Let us rewrite the above expression, we will get:
$ \Rightarrow {x^3} + 4{x^2} + 8x + 32$
Therefore, by performing the reverse process we will get our given expression back.
Hence, it is proved that our answer is right.
Complete step-by-step answer:
In this question, we want to factor the expression ${x^3} + 4{x^2} + 8x + 32$ by grouping the terms.
Let us make a pair of terms of the given expression.
$ \Rightarrow {x^3} + 4{x^2} + 8x + 32$
Now, the first group has the first two terms, and the second group has another two terms.
Here, the first group will be ${x^3} + 4{x^2}$ , and the second group will be $8x + 32$
So, let us write them into brackets.
$ \Rightarrow \left( {{x^3} + 4{x^2}} \right) + \left( {8x + 32} \right)$
Now, take out the greatest common factor from each group.
In the first group, ${x^2}$ is the greatest common factor.
And in the second group, 8 is the greatest common factor.
Therefore, we will get:
$ \Rightarrow {x^2}\left( {x + 4} \right) + 8\left( {x + 4} \right)$
Now, take out the common term to get factors.
Here, $x + 4$ is the common term in the above expression.
So, we will get:
$ \Rightarrow \left( {x + 4} \right)\left( {{x^2} + 8} \right)$
Hence, the factors of the given expression ${x^3} + 4{x^2} + 8x + 32$ are $x + 4$ and ${x^2} + 8$.
Note:
One important thing is, we can always check our work by multiplying out factors back together, and check that we have got back the original answer.
To check our factorization, multiplication goes like this:
$ \Rightarrow \left( {x + 4} \right)\left( {{x^2} + 8} \right)$
Break the first bracket and multiply it with another bracket.
So,
$ \Rightarrow x\left( {{x^2} + 8} \right) + 4\left( {{x^2} + 8} \right)$
Let us apply multiplication to remove brackets.
$ \Rightarrow {x^3} + 8x + 4{x^2} + 32$
Let us rewrite the above expression, we will get:
$ \Rightarrow {x^3} + 4{x^2} + 8x + 32$
Therefore, by performing the reverse process we will get our given expression back.
Hence, it is proved that our answer is right.
Recently Updated Pages
If x a + bt + ct2 where x is in meters and t is in class 11 physics CBSE

A car covers the first half distance between two places class 11 physics CBSE

The resultant of two vectors overrightarrow P and overrightarrow class 11 physics CBSE

Find the value of cos 135 class 11 maths CBSE

A mass M is held in place by an applied force F and class 11 physics CBSE

A solution of glucose in water is labelled as 10 dfracwv class 11 chemistry CBSE

Trending doubts
Find the value of the expression given below sin 30circ class 11 maths CBSE

One Metric ton is equal to kg A 10000 B 1000 C 100 class 11 physics CBSE

Draw a diagram of nephron and explain its structur class 11 biology CBSE

10 examples of friction in our daily life

Proton was discovered by A Thomson B Rutherford C Chadwick class 11 chemistry CBSE

Bond order ofO2 O2+ O2 and O22 is in order A O2 langle class 11 chemistry CBSE

