Example of an improper fraction is –
$\left( A \right)\,\,\dfrac{{35}}{{36}}$
$\left( B \right)\,\,\dfrac{{20}}{{10}}$
$\left( C \right)\,\,\dfrac{{12}}{{14}}$
$\left( D \right)\,\,\dfrac{{17}}{{20}}$

Hint: One of the most important things to do with this question is that the number in which the value of numerator is greater than the value of denominator is an example of improper fraction. We can also write improper fractions in the form of mixed fractions.

Complete step by step solution:
In the given question,
We can see that there are four options and the only option is correct in which the numerator part is greater than the denominator part.
For example- $\dfrac{{15}}{{12}},\,\,\dfrac{8}{3},\,\,\dfrac{9}{2},\,\,\dfrac{{10}}{4}\,\,etc.$
Therefore, we can see that $\dfrac{{20}}{{10}}$ is the only number in which the numerator part is greater than the denominator part.
Generally, we can also write an improper fraction in the form of a mixed fraction.
For example- $\dfrac{{13}}{{10}} = 1\dfrac{3}{{10}}\,\,and\,\,\dfrac{5}{3}\, = \,1\dfrac{2}{3}\,.$
Hence, the correct option is $\left( B \right).$

Note: In a Proper Fraction, the numerator is smaller than the denominator. Normal fractions are proper fractions. Examples of the proper fraction are $\dfrac{2}{5},\,\dfrac{8}{{15}},\,\dfrac{5}{8}$ etc. The numerators are \[2,8,5\] and the denominators are\[5,{\text{ }}15,{\text{ }}8\] . Here the numerators \[2,8,5\] are less than the denominators \[5,{\text{ }}15,{\text{ }}8.\] Further simplification of the value of the proper fraction is always less than one and greater than zero. In an Improper Fraction, the numerator is larger than the denominator. Further simplification of the improper fraction gives the value equal to 1 and greater than one but not less than one. By adding one or more whole numbers and one proper fraction we get an Improper fraction.