How does one simplify $\dfrac{{24}}{{\sqrt 3 }}$ ?
Answer
617.4k+ views
Hint: For solving this particular question , we have to rationalize the given number denominator by respective number, then simplify the expression by using algebraic identities and by performing arithmetic operations such as addition , subtraction , multiplication, and division . We have to convert numbers into its equivalent exponential form where required.
Formula used:In this particular question we used an identity that is ,
${a^m} \times {a^n} = {a^{m + n}}$ , exponent gets added when we have the same base.
Complete step-by-step solution:
We have to simplify the given expression that is $\dfrac{{24}}{{\sqrt 3 }}$. Now, to rationalize the denominator of the given number by multiplying and divide the given number by $\sqrt 3 $ , we have to rationalize the given number denominator by its respective conjugate. The process of multiplying and dividing by the conjugate is a useful technique , this will make the expression simpler.
We will get the following ,
$ \Rightarrow \dfrac{{24}}{{\sqrt 3 }} \times \dfrac{{\sqrt 3 }}{{\sqrt 3 }}$
Now by using algebraic identity that is , ${a^m} \times {a^n} = {a^{m + n}}$ , We will get the following ,
$ \Rightarrow \dfrac{{24\sqrt 3 }}{3}$
Simplify the above expression by performing valid arithmetic operation ,
$ \Rightarrow 8\sqrt 3 $
In exact form
$ \Rightarrow 8\sqrt 3 $
In decimal form
$ \Rightarrow 13.85640646$
Here, we get the required answer .
Hence the correct answer is $13.85640646$
Note: While rationalizing the given number denominator , you have to make sure that the resulting product must be the simpler one. Here we have to multiply and divide the number by its respective conjugate and this is a useful technique that comes up in mathematics. We have to be careful while adding the exponents of the numbers having the same base.
Formula used:In this particular question we used an identity that is ,
${a^m} \times {a^n} = {a^{m + n}}$ , exponent gets added when we have the same base.
Complete step-by-step solution:
We have to simplify the given expression that is $\dfrac{{24}}{{\sqrt 3 }}$. Now, to rationalize the denominator of the given number by multiplying and divide the given number by $\sqrt 3 $ , we have to rationalize the given number denominator by its respective conjugate. The process of multiplying and dividing by the conjugate is a useful technique , this will make the expression simpler.
We will get the following ,
$ \Rightarrow \dfrac{{24}}{{\sqrt 3 }} \times \dfrac{{\sqrt 3 }}{{\sqrt 3 }}$
Now by using algebraic identity that is , ${a^m} \times {a^n} = {a^{m + n}}$ , We will get the following ,
$ \Rightarrow \dfrac{{24\sqrt 3 }}{3}$
Simplify the above expression by performing valid arithmetic operation ,
$ \Rightarrow 8\sqrt 3 $
In exact form
$ \Rightarrow 8\sqrt 3 $
In decimal form
$ \Rightarrow 13.85640646$
Here, we get the required answer .
Hence the correct answer is $13.85640646$
Note: While rationalizing the given number denominator , you have to make sure that the resulting product must be the simpler one. Here we have to multiply and divide the number by its respective conjugate and this is a useful technique that comes up in mathematics. We have to be careful while adding the exponents of the numbers having the same base.
Recently Updated Pages
Explain the Treaty of Vienna of 1815 class 10 social science CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

A Paragraph on Pollution in about 100-150 Words

XIX+XXX A 49 B 51 C 55 D 44 class 5 maths CBSE

Trending doubts
What is BLO What is the full form of BLO class 8 social science CBSE

Citizens of India can vote at the age of A 18 years class 8 social science CBSE

Full form of STD, ISD and PCO

Write an article on Global warming in about 200 words

What are the methods of reducing friction. Explain

Write a letter to the Municipal Commissioner to inform class 8 english CBSE


