A road 14m wide surrounded a circular park whose circumference is 704m. Find the surface area of the road. Also, find the cost of paying the road at Rs 100 per \[{m^2}\]
Answer
663.3k+ views
Hint: A road 14m wide surrounded by a circular both must be circular as well.
Circumference of a circle is the perimeter i.e. length of outer boundary of the circle.
Hence formula of circumference of a circle is
\[ = 2\pi r\] where \[l = \] radius of circle and \[\pi = \dfrac{{22}}{7}\]
As we know that road is surrounded by a circular park i.e., they are forming concentric circles.
Area of concentric circle \[ = \pi ({R^2} - {r^2})\], where
R= outer radius of the circle
R= Inner radius of the circle and \[R = width + r\]
Complete step by step solution:
Given,
Circumference of a circular park \[ = 704m\]
Width of a road\[ = 14m\]
Circumference of a circle \[ = 2\pi \]
\[
704 = 2 \times \dfrac{{22}}{7} \times r \\
704 \times 7 = 44r \\
r = \dfrac{{704 \times 7}}{{44}} \\
r = 16 \times 7 \\
r = 112m \\
\]
Inner radius of the park i.e. \[r = 112m\]
Outer radius of the park i.e. \[R = width + r\]
\[
\Rightarrow R = 14 + 112 = 126m \\
\Rightarrow R = 126m \\
\]
Area of the road \[
= \pi ({R^2} - {r^2}) \\
\Rightarrow \pi (R + r)(R - r) \\
\] By using identify \[[{a^2} - {b^2} = (a - b)(a + b)]\]
\[
\Rightarrow \dfrac{{22}}{7}(126 + 112)(126 - 112) \\
\Rightarrow \dfrac{{22}}{7} \times 238 \times 14 \\
\Rightarrow 22 \times 238 \times 2 \\
\Rightarrow 238 \times 44 \\
\Rightarrow 10472\,{m^2} \\
\]
Hence, Area of the road \[ = 10472\,{m^2}\]
Cost of paving \[1{m^2}\]road \[ = Rs\,100\]
Cost of paving \[10472\,{m^2}\]road \[
= Rs\,100 \times 10472 \\
= Rs\,1047200 \\
\]
Note: The circles with a common center point are known as concentric circles. In other words. It is defined as two or more circles that have the same center point. The region between two concentric circles of different radii is known as an annulus.
In the concept of concentric circles, one circle is inscribed in the other. Hence there are two types of radius i.e. Outer radius denoted by R and inner radius i.e. r.
Circumference of a circle is the perimeter i.e. length of outer boundary of the circle.
Hence formula of circumference of a circle is
\[ = 2\pi r\] where \[l = \] radius of circle and \[\pi = \dfrac{{22}}{7}\]
As we know that road is surrounded by a circular park i.e., they are forming concentric circles.
Area of concentric circle \[ = \pi ({R^2} - {r^2})\], where
R= outer radius of the circle
R= Inner radius of the circle and \[R = width + r\]
Complete step by step solution:
Given,
Circumference of a circular park \[ = 704m\]
Width of a road\[ = 14m\]
Circumference of a circle \[ = 2\pi \]
\[
704 = 2 \times \dfrac{{22}}{7} \times r \\
704 \times 7 = 44r \\
r = \dfrac{{704 \times 7}}{{44}} \\
r = 16 \times 7 \\
r = 112m \\
\]
Inner radius of the park i.e. \[r = 112m\]
Outer radius of the park i.e. \[R = width + r\]
\[
\Rightarrow R = 14 + 112 = 126m \\
\Rightarrow R = 126m \\
\]
Area of the road \[
= \pi ({R^2} - {r^2}) \\
\Rightarrow \pi (R + r)(R - r) \\
\] By using identify \[[{a^2} - {b^2} = (a - b)(a + b)]\]
\[
\Rightarrow \dfrac{{22}}{7}(126 + 112)(126 - 112) \\
\Rightarrow \dfrac{{22}}{7} \times 238 \times 14 \\
\Rightarrow 22 \times 238 \times 2 \\
\Rightarrow 238 \times 44 \\
\Rightarrow 10472\,{m^2} \\
\]
Hence, Area of the road \[ = 10472\,{m^2}\]
Cost of paving \[1{m^2}\]road \[ = Rs\,100\]
Cost of paving \[10472\,{m^2}\]road \[
= Rs\,100 \times 10472 \\
= Rs\,1047200 \\
\]
Note: The circles with a common center point are known as concentric circles. In other words. It is defined as two or more circles that have the same center point. The region between two concentric circles of different radii is known as an annulus.
In the concept of concentric circles, one circle is inscribed in the other. Hence there are two types of radius i.e. Outer radius denoted by R and inner radius i.e. r.
Recently Updated Pages
What is BLO What is the full form of BLO class 8 social science CBSE

Explain the Treaty of Vienna of 1815 class 10 social science CBSE

10 examples of friction in our daily life

Draw a diagram of nephron and explain its structur class 11 biology CBSE

Write structures of the following compounds i 2 Chloro3methylpentane class 11 chemistry CBSE

A Paragraph on Pollution in about 100-150 Words

Trending doubts
Draw a labelled sketch of the human eye class 12 physics CBSE

Which are the Top 10 Largest Countries of the World?

Differentiate between homogeneous and heterogeneous class 12 chemistry CBSE

Draw ray diagrams each showing i myopic eye and ii class 12 physics CBSE

Which is the correct genotypic ratio of mendel dihybrid class 12 biology CBSE

What is the Full Form of PVC, PET, HDPE, LDPE, PP and PS ?

