$C{{H}_{3}}COOH\xrightarrow{CaC{{O}_{3}}}A\xrightarrow{Heat}B\xrightarrow{N{{H}_{2}}OH}C$
The end product of reaction is:

Hint: Here when calcium carbonate reacts with carboxylic group it produces product A. It is calcium salt of acetic acid which when heated gives product B, a common organic solvent with low boiling point and the reaction of product B and Hydroxylamine gives product C which is the simplest ketoxime.

Complete step by step answer:
Let us first discuss carboxylic acid. Those compounds which contains a carboxyl $(-COOH)$ functional group are known as carboxylic acids, they are the derivative of hydrocarbon in which one or hydrogen atom are replaced by carboxylic group, the common formula to write carboxylic acid is ${{C}_{n}}{{H}_{2n}}{{O}_{2}}$.

It is a combination of two groups hydroxyl and carbonyl but they do not show properties of both groups.
And now discuss Calcium Carbonate, if we talk about its physical states so it is a white powder like substance it is also insoluble and occurs in minerals, chalk, marble, limestone, pearl, etc. And it is also used as an antacid as a calcium in medicines. When calcium carbonate reacts with an acidic solution it produces carbon dioxide gas as we can see when we put hydrochloric acid on limestone and then the limestone starts fizzing that is due to release of carbon dioxide gas.

And now it’s time to discuss about Hydroxylamine which is an inorganic compound with the formula$N{{H}_{2}}OH$ it is appear as white when it is pure material as when it’s comes to its uses it is
used to prepare oximes which is an important functional group.

Now coming back to our reaction which is
$C{{H}_{3}}COOH\xrightarrow{CaC{{O}_{3}}}A\xrightarrow{Heat}B\xrightarrow{N{{H}_{2}}OH}C$

Here when we solve it we get our reaction as
$C{{H}_{3}}COOH\xrightarrow{CaC{{O}_{3}}}{{(C{{H}_{3}}COO)}_{2}}Ca\xrightarrow{Heat}C{{H}_{3}}COC{{H}_{3}}\xrightarrow{N{{H}_{2}}OH}{{(C{{H}_{3}})}_{2}}C=NOH$
($Acetic-acid$) ($Calcium-acetate$) ($Acetone$) ($Acetoxime$)

 Where A product is: ${{(C{{H}_{3}}COO)}_{2}}Ca$
     B product is: $C{{H}_{3}}COC{{H}_{3}}$
     C product is: ${{(C{{H}_{3}})}_{2}}C=NOH$
So our end product is Acetoxime.

Note: Aldehyde and ketones both have one carbonyl group present so they are called carbonyl group and both of them show functional isomerism.
When we use ammonia derivatives like Hydroxylamine it produces Oximes as we can see in our above reaction.